Трябва да направите 3-посочно ПРИСЪЕДИНЯВАНЕ:
CREATE TABLE new_table AS
SELECT p.*, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'
Или ако вече сте създали таблицата, можете да направите:
INSERT INTO new_table (id, last_name, first_name, email, age)
SELECT p.id, p.last_name, p.first_name, p.email, d.content AS age
FROM people AS p
JOIN details AS d ON d.person_id = p.id
JOIN taxonomy AS t ON t.id = d.detail_id
WHERE t.taxonomy = 'age'
За да получите множество атрибути, трябва да се присъедините към таблиците с подробности и таксономия поотделно за всеки атрибут:
CREATE TABLE new_table AS
SELECT p.*, d1.content AS age, d2.content AS gender, d3.content AS height
FROM people AS p
JOIN details AS d1 ON d1.person_id = p.id
JOIN taxonomy AS t1 ON t1.id = d1.detail_id
JOIN details AS d2 ON d2.person_id = p.id
JOIN taxonomy AS t2 ON t2.id = d2.detail_id
JOIN details AS d3 ON d3.person_id = p.id
JOIN taxonomy AS t3 ON t3.id = d3.detail_id
WHERE t1.taxonomy = 'age' AND t2.taxonomy = 'gender' AND t3.taxonomy = 'height'