Изберете брой отговори на MCQ въз основа на отговора на предишния въпрос

Ако не искате да правите mod, тогава трябва да изберете questionID вместо това. Използвах кръстосано свързване за да получите друг сегмент, където няма отговор. и в командата select вие case оператор за преброяване на segmentName до 0.

SELECT
    bb.name,
    s.name,
    CASE WHEN s.id IN(
        SELECT
            r.segment_id FROM brandlift_respondent r) THEN
        COUNT(q2ac.brand_id)
    ELSE
        0
    END AS CountNumber
FROM
    brandlift b
    LEFT JOIN brandlift_brand bb ON b.campaign_id = bb.campaign_id
    LEFT JOIN brandlift_respondent r ON b.campaign_id = r.campaign_id
    
    CROSS JOIN brandlift_segment s
    
    LEFT JOIN brandlift_question q1 ON b.campaign_id = q1.campaign_id AND q1.ordinal = 1
    LEFT JOIN brandlift_answer q1a ON r.id = q1a.respondent_id AND q1.id = q1a.question_id
    INNER JOIN brandlift_answer_content q1ac ON q1a.id = q1ac.answer_id AND q1ac.brand_id = 1 -- the "flagship brand" id
        
    LEFT JOIN brandlift_question q2 ON q1.campaign_id = q2.campaign_id AND q2.ordinal = 2
    LEFT JOIN brandlift_answer q2a ON q1a.respondent_id = q2a.respondent_id AND q2.id = q2a.question_id
    LEFT JOIN brandlift_answer_content q2ac ON q2a.id = q2ac.answer_id AND bb.id = q2ac.brand_id
WHERE
    b.campaign_id = :campaign_id -- parameter
    AND R.segment_id = s.id OR s.id NOT IN(SELECT r.segment_id FROM brandlift_respondent r)
GROUP BY
    bb.name,
    s.name,
    s.id

резултатът показва така