Следната заявка ще предостави същия резултат като \l+
в psql
от PostgreSQL 9.4.1:
SELECT
d.datname as "Name",
pg_catalog.pg_get_userbyid(d.datdba) as "Owner",
pg_catalog.pg_encoding_to_char(d.encoding) as "Encoding",
d.datcollate as "Collate",
d.datctype as "Ctype",
pg_catalog.array_to_string(d.datacl, E'\n') as "Access privileges",
CASE WHEN pg_catalog.has_database_privilege(d.datname, 'CONNECT')
THEN pg_catalog.pg_size_pretty(pg_catalog.pg_database_size(d.datname))
ELSE 'No Access'
END as "Size",
t.spcname as "Tablespace",
pg_catalog.shobj_description(d.oid, 'pg_database') as "Description"
FROM
pg_catalog.pg_database d
JOIN
pg_catalog.pg_tablespace t on d.dattablespace = t.oid
ORDER BY 1;
Ето източника:src/ bin/psql/describe.c