Как да направя неудобно завъртане на sql таблица в SQL Server 2005?

Това трябва да ви оправи. Това наистина е UNPIVOT и PIVOT. Обърнете внимание, че трябва да съобразите данните си, защото UNPIVOT поставя всички данни в една и съща колона.

Обърнете внимание, че трябваше да създам отново/попълня отново променливата на таблицата във вътрешния динамичен SQL - обикновено това не е необходимо, когато работим с постоянна таблица.

SET NOCOUNT ON ;

DECLARE @pivot_cols AS varchar(max) ;
DECLARE @src AS TABLE
    (
     ID int NOT NULL
    ,Label varchar(14) NOT NULL
    ,Numerator int NOT NULL
    ,Denominator int NOT NULL
    ,Ratio decimal(5, 4) NOT NULL
    ) ;

DECLARE @label_order AS TABLE
    (
     Label varchar(14) NOT NULL
    ,Sort int NOT NULL
    )

INSERT  INTO @src
VALUES  (1, 'LabelNameOne', 41, 10, 4.1) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameThree', 21, 10, 2.1) ;
INSERT  INTO @src
VALUES  (1, 'LabelNameFour', 15, 10, 1.5) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameOne', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameThree', 15, 16, 0.9375) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameFive', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, 'LabelNameSix', 17, 17, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameOne', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameTwo', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameThree', 11, 12, 0.9167) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameFour', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, 'LabelNameSix', 0, 1, 0) ;

INSERT  INTO @label_order
VALUES  ('LabelNameOne', 1) ;
INSERT  INTO @label_order
VALUES  ('LabelNameTwo', 2) ;
INSERT  INTO @label_order
VALUES  ('LabelNameThree', 3) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFour', 4) ;
INSERT  INTO @label_order
VALUES  ('LabelNameFive', 5) ;
INSERT  INTO @label_order
VALUES  ('LabelNameSix', 6) ;

WITH    Labels
          AS (
              SELECT  DISTINCT
                        src.Label
                       ,ISNULL(label_order.Sort, 0) AS Sort
              FROM      @src AS src
              LEFT JOIN @label_order AS label_order
                        ON src.label = label_order.label
             )
    SELECT  @pivot_cols = COALESCE(@pivot_cols + ',', '') + QUOTENAME(Label, '[')
    FROM    Labels
    ORDER BY Sort
           ,Label ;

DECLARE @template AS varchar(max) ;

SET @template = '
DECLARE @src AS TABLE
    (
     ID int NOT NULL
    ,Label varchar(14) NOT NULL
    ,Numerator int NOT NULL
    ,Denominator int NOT NULL
    ,Ratio decimal(5, 4) NOT NULL
    ) ;

INSERT  INTO @src
VALUES  (1, ''LabelNameOne'', 41, 10, 4.1) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameThree'', 21, 10, 2.1) ;
INSERT  INTO @src
VALUES  (1, ''LabelNameFour'', 15, 10, 1.5) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameOne'', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameThree'', 15, 16, 0.9375) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameFive'', 19, 19, 1) ;
INSERT  INTO @src
VALUES  (2, ''LabelNameSix'', 17, 17, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameOne'', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameTwo'', 0, 0, 0) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameThree'', 11, 12, 0.9167) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameFour'', 12, 12, 1) ;
INSERT  INTO @src
VALUES  (3, ''LabelNameSix'', 0, 1, 0) ;

WITH    src_conformed
          AS (
              SELECT    ID
                       ,Label
                       ,CAST (Numerator AS decimal(10, 4)) AS Numerator
                       ,CAST (Denominator AS decimal(10, 4)) AS Denominator
                       ,CAST (Ratio AS decimal(10, 4)) AS Ratio
              FROM      @src
             ),
        UNPIVOTED
          AS (
              SELECT    *
              FROM      src_conformed UNPIVOT ( Val FOR Col IN (Numerator, Denominator, Ratio) ) AS unpvt
             )
    SELECT  *
    FROM    UNPIVOTED PIVOT ( SUM(Val) FOR Label IN ({@pivot_cols}) ) AS pvt
    ORDER BY ID
           ,Col ;' ;

SET @template = REPLACE(@template, '{@pivot_cols}', @pivot_cols) ;

EXEC (@template) ;