Как мога да разделя стойността на колоната на различни колони в SQL

declare @T table
(
  col_1 varchar(100)
)

insert into @T values
('aa,ab,ac,4,5,6,7,8,9,10'),
('ba,bb,bc,4,5,6,7,8,9,10'),
('ca,cb,cc,4,5,6,7,8,9,10')

select left(T.col_1, C1.Pos-1) as col_1,
       substring(T.col_1, C1.Pos+1, C2.Pos-C1.Pos-1)  as col_2,
       substring(T.col_1, C2.Pos+1, C3.Pos-C2.Pos-1)  as col_3,
       substring(T.col_1, C3.Pos+1, C4.Pos-C3.Pos-1)  as col_4,
       substring(T.col_1, C4.Pos+1, C5.Pos-C4.Pos-1)  as col_5,
       substring(T.col_1, C5.Pos+1, C6.Pos-C5.Pos-1)  as col_6,
       substring(T.col_1, C6.Pos+1, C7.Pos-C6.Pos-1)  as col_7,
       substring(T.col_1, C7.Pos+1, C8.Pos-C7.Pos-1)  as col_8,
       substring(T.col_1, C8.Pos+1, C9.Pos-C8.Pos-1)  as col_9,
       stuff(T.col_1, 1, C9.Pos, '') as col_10
from @T as T
  cross apply (select charindex(',', col_1)) as C1(Pos)
  cross apply (select charindex(',', col_1, C1.Pos+1)) as C2(Pos)
  cross apply (select charindex(',', col_1, C2.Pos+1)) as C3(Pos)
  cross apply (select charindex(',', col_1, C3.Pos+1)) as C4(Pos)
  cross apply (select charindex(',', col_1, C4.Pos+1)) as C5(Pos)
  cross apply (select charindex(',', col_1, C5.Pos+1)) as C6(Pos)
  cross apply (select charindex(',', col_1, C6.Pos+1)) as C7(Pos)
  cross apply (select charindex(',', col_1, C7.Pos+1)) as C8(Pos)
  cross apply (select charindex(',', col_1, C8.Pos+1)) as C9(Pos)