SQL - Клониране на запис и неговите наследници

Както Мартин предложи, трябва да активирате IDENTITY_INSERT така че да можете да прокарате собствените си ценности за идентичност. Може също да се наложи да придобиете заключване на таблица, за да сте сигурни, че Max( Id) връща правилната стойност.

If object_id('tempdb..#TestData') is not null
    Drop Table #TestData
GO
Create Table #TestData
    (
    Id int not null identity(1,1) Primary Key
    , ParentId int not null
    , Name varchar(50) not null
    )
GO
Set Identity_Insert #TestData On
GO  
Insert #TestData( Id, ParentId, Name )
Values( 1,0,'Food' )
    , ( 2,1,'Taste' )
    , ( 3,1,'Price' )
    , ( 4,2,'Taste Requirement' );


With Data As
    (
    Select Cast(MaxId.Id + 1 As int) As Id
        , T.ParentId
        , 'Copy Of ' + T.name As Name
        , T.Id As OldId
        , 0 As OldParentId
    From #TestData As T
        Cross Join( Select Max( id ) As Id From #TestData ) As MaxId
    Where T.Name = 'Food'
    Union All
    Select Cast(Parent.id + Row_Number() Over( Order By Child.Id ) + 1 As int)
        , Parent.Id
        , 'Copy of ' + Child.Name
        , Child.Id
        , Child.ParentId
    From Data As Parent
        Join #TestData As Child
            On Child.ParentId = Parent.OldId
    )
Insert #TestData( Id, ParentId, Name )
Select Id, ParentId, Name
From Data
GO
Set Identity_Insert #TestData Off
GO  

Резултати

id | parentid | name
-- | -------- | -----------------
1  | 0        | Food
2  | 1        | Taste
3  | 1        | Price
4  | 2        | Taste Requirement
5  | 0        | Copy Of Food
7  | 5        | Copy of Taste
8  | 5        | Copy of Price
9  | 7        | Copy of Taste Requirement