Намерете липсващите дати и ги добавете в резултат - MySql

може да не е идеалното решение, но това може да ви даде резултата:втората заявка след UNION ALL във вътрешния SELECT трябва да върне всички дати между MIN(created) и MAX(created) от вашата таблица със стойност на брояча 0.

    SELECT SUM(a.ctr)
      ,a.datecreated
  FROM 
  (

    SELECT COUNT(*) as ctr, date_format(created, '%d/%m/%y ') as datecreated 
    FROM mimesi_indexer.meta_served_clips
    GROUP BY DATE(created)
UNION ALL 
    select 0 as ctr, date_format(selected_date, '%d/%m/%y ') as datecreated 
       from 
     (select adddate('1970-01-01',t4.i*10000 + t3.i*1000 + t2.i*100 + t1.i*10 + t0.i) selected_date from
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t0,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t1,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t2,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t3,
     (select 0 i union select 1 union select 2 union select 3 union select 4 union select 5 union select 6 union select 7 union select 8 union select 9) t4) v
    where selected_date 
    between (SELECT MIN(created) FROM mimesi_indexer.meta_served_clips)
        and (SELECT MAX(created) FROM mimesi_indexer.meta_served_clips)
   ) a
   group by a.datecreated
   order by month(a.datecreated), date(a.datecreated)