запитване за класиране на потребителя в таблици "един към много".

SELECT u.id,total_score,
 ( SELECT COUNT(*) FROM
    (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
     FROM users u1
     LEFT JOIN games g ON (g.userId = u1.id)
     GROUP BY u1.id
    )x1
   WHERE x1.total_score > x.total_score
 )+1 as rank,

( SELECT COUNT(DISTINCT total_score) FROM
    (SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
     FROM users u1
     LEFT JOIN games g ON (g.userId_Id = u1.id)
     GROUP BY u1.id
    )x1
   WHERE x1.total_score > x.total_score
 )+1 as dns_rank

 FROM users u

 LEFT JOIN
  ( SELECT u1.id, (IFNULL(u1.freebee,0)+ IFNULL(SUM(score),0)) as total_score
    FROM users u1
    LEFT JOIN games g ON (g.userId = u1.id)
    GROUP BY u1.id
  )x ON (x.id = u.id)

rank - (нормален ранг - напр. - 1,2,2,4,5), dns_rank - плътен ранг (1,2,2,3,4). Колона total_score - само за отстраняване на грешки...