Не познавах функцията find_in_set() и използвах по-ръчно изработен подход. Не че има някакъв смисъл предвид първия отговор, но все пак ще го публикувам:
SELECT id
FROM (
SELECT '757392' AS id UNION
SELECT '733602' UNION
SELECT '749955' UNION
SELECT '744304' UNION
SELECT '746852' UNION
SELECT '753904' UNION
SELECT '755117' UNION
SELECT '636163' UNION
SELECT '564931' UNION
SELECT '740787' UNION
SELECT '751450' UNION
SELECT '743799' UNION
SELECT '643918' UNION
SELECT '749903' UNION
SELECT '571888' UNION
SELECT '30207' UNION
SELECT '705953' UNION
SELECT '749120' UNION
SELECT '749001' UNION
SELECT '749192' UNION
SELECT '749978' UNION
SELECT '750840' UNION
SELECT '544228' UNION
SELECT '702121' UNION
SELECT '746246' UNION
SELECT '383667' UNION
SELECT '558790' UNION
SELECT '585628' UNION
SELECT '592771' UNION
SELECT '745818' UNION
SELECT '749375' UNION
SELECT '241209' UNION
SELECT '749235' UNION
SELECT '746860' UNION
SELECT '748318' UNION
SELECT '748016' UNION
SELECT '748951' UNION
SELECT '747321' UNION
SELECT '748684' UNION
SELECT '748225' UNION
SELECT '565375' UNION
SELECT '748673' UNION
SELECT '747869' UNION
SELECT '748522' UNION
SELECT '748335' UNION
SELECT '744775' UNION
SELECT '672229' UNION
SELECT '578056' UNION
SELECT '713127' UNION
SELECT '740234' UNION
SELECT '632608' UNION
SELECT '711135' UNION
SELECT '746528' UNION
SELECT '362131' UNION
SELECT '742223' UNION
SELECT '746567' UNION
SELECT '745224' UNION
SELECT '332989' UNION
SELECT '439837' UNION
SELECT '745418' UNION
SELECT '673582' UNION
SELECT '269584' UNION
SELECT '742606' UNION
SELECT '745135' UNION
SELECT '746950' UNION
SELECT '476134' UNION
SELECT '740830' UNION
SELECT '742949' UNION
SELECT '276934') AS id_list
WHERE id NOT IN (
SELECT id
FROM users);