SELECT City, Count(City) As theCount
FROM (Select City, State From tblCityStateZips Group By City, State) As C
GROUP By City
HAVING COUNT Count(City) > 1
Това ще върне всички градове с брой, които се съдържат в повече от един щат.
Greenville 39
Greenwood 2
GreenBriar 3
и др.