MySqlCommand Command.Parameters.Add е остарял

опитайте AddWithValue

command.Parameters.AddWithValue("@mcUserName", mcUserNameNew);
command.Parameters.AddWithValue("@mcUserPass", mcUserPassNew);
command.Parameters.AddWithValue("@twUserName", twUserNameNew);
command.Parameters.AddWithValue("@twUserPass", twUserPassNew);

и не обвивайте заместителите с единични кавички.

string SQL = "INSERT INTO `twMCUserDB` (`mc_userName`, `mc_userPass`, `tw_userName`, `tw_userPass`) VALUES (@mcUserName, @mcUserPass, @twUserName, @twUserPass)";