Както @be here now вече отбеляза в коментара, Oracle не предоставя такава функция. Така че като бързо решение можете да напишете подобна заявка:
with t1(user_id, degree_fi, degree_en, degree_sv) as
(
select 3601464, '3700', '1600', '2200' from dual union all
select 1020 , '100' , '0' , '0' from dual union all
select 3600520, '100,3200,400', '1300, 800, 3000', '1400, 600, 1500' from dual union all
select 3600882, '0', '100', '200' from dual
),
Occurence(ocr) as(
select Level as ocr
from (select max(greatest(regexp_count(degree_fi, '[^,]+')
, regexp_count(degree_en, '[^,]+')
, regexp_count(degree_sv, '[^,]+')
)
) mx
from t1
)
connect by level <= mx
)
select *
from (
select User_id
, regexp_substr(degree_fi, '[^,]+', 1, o.ocr) as degree_fi
, regexp_substr(degree_en, '[^,]+', 1, o.ocr) as degree_en
, regexp_substr(degree_sv, '[^,]+', 1, o.ocr) as degree_sv
from t1 t
cross join Occurence o
)
where degree_fi is not null
or degree_en is not null
or degree_sv is not null
Резултат:
User_Id Degree_Fi Degree_En Degree_Sv
------------------------------------------------------------
3601464 3700 1600 2200
1020 100 0 0
3600520 100 1300 1400
3600882 0 100 200
3600520 3200 800 600
3600520 400 3000 1500