Нещо подобно, ако приемем, че created_at
е от тип date
select p.name,
hc.note as current_note,
av.avg_note
from patients p
join health_conditions hc on hc.patient_id = p.id
join (
select patient_id,
avg(note) as avg_note
from health_conditions hc2
where created_at between current_date - 30 and current_date - 1
group by patient_id
) avg on t.patient_id = hc.patient_id
where hc.created_at = current_date;
Това е синтаксисът на PostgreSQL. Не съм сигурен дали MySQL поддържа аритметика с дати по същия начин.
Редактиране:
Това трябва да ви даде най-новата бележка за всеки пациент, плюс средната стойност за последните 30 дни:
select p.name,
hc.created_at as last_note_date
hc.note as current_note,
t.avg_note
from patients p
join health_conditions hc
on hc.patient_id = p.id
and hc.created_at = (select max(created_at)
from health_conditions hc2
where hc2.patient_id = hc.patient_id)
join (
select patient_id,
avg(note) as avg_note
from health_conditions hc3
where created_at between current_date - 30 and current_date - 1
group by patient_id
) t on t.patient_id = hc.patient_id