Sqlserver
 sql >> база данни >  >> RDS >> Sqlserver

Как да направя допълнителни колони в опорната точка на sql таблица в SQL Server 2005?

Трябва да комбинирате етикетите преди PIVOT. Списъкът с колони също трябва да вземе предвид възможностите за кръстосано свързване на етикети:

SET NOCOUNT ON ; 

DECLARE @pivot_cols AS varchar(max) ; 
DECLARE @src AS TABLE 
    ( 
     ID int NOT NULL 
    ,Label varchar(14) NOT NULL 
    ,Numerator int NOT NULL 
    ,Denominator int NOT NULL 
    ,Ratio decimal(5, 4) NOT NULL 
    ) ; 

DECLARE @label_order AS TABLE 
    ( 
     Label varchar(14) NOT NULL 
    ,Sort int NOT NULL 
    ) 

DECLARE @sub_label_order AS TABLE 
    ( 
     SubLabel varchar(14) NOT NULL 
    ,Sort int NOT NULL 
    ) 

INSERT  INTO @src 
VALUES  (1, 'LabelNameOne', 41, 10, 4.1) ; 
INSERT  INTO @src 
VALUES  (1, 'LabelNameTwo', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (1, 'LabelNameThree', 21, 10, 2.1) ; 
INSERT  INTO @src 
VALUES  (1, 'LabelNameFour', 15, 10, 1.5) ; 
INSERT  INTO @src 
VALUES  (2, 'LabelNameOne', 19, 19, 1) ; 
INSERT  INTO @src 
VALUES  (2, 'LabelNameTwo', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (2, 'LabelNameThree', 15, 16, 0.9375) ; 
INSERT  INTO @src 
VALUES  (2, 'LabelNameFive', 19, 19, 1) ; 
INSERT  INTO @src 
VALUES  (2, 'LabelNameSix', 17, 17, 1) ; 
INSERT  INTO @src 
VALUES  (3, 'LabelNameOne', 12, 12, 1) ; 
INSERT  INTO @src 
VALUES  (3, 'LabelNameTwo', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (3, 'LabelNameThree', 11, 12, 0.9167) ; 
INSERT  INTO @src 
VALUES  (3, 'LabelNameFour', 12, 12, 1) ; 
INSERT  INTO @src 
VALUES  (3, 'LabelNameSix', 0, 1, 0) ; 

INSERT  INTO @label_order 
VALUES  ('LabelNameOne', 1) ; 
INSERT  INTO @label_order 
VALUES  ('LabelNameTwo', 2) ; 
INSERT  INTO @label_order 
VALUES  ('LabelNameThree', 3) ; 
INSERT  INTO @label_order 
VALUES  ('LabelNameFour', 4) ; 
INSERT  INTO @label_order 
VALUES  ('LabelNameFive', 5) ; 
INSERT  INTO @label_order 
VALUES  ('LabelNameSix', 6) ; 

INSERT  INTO @sub_label_order 
VALUES  ('Numerator', 1) ; 
INSERT  INTO @sub_label_order 
VALUES  ('Denominator', 2) ; 
INSERT  INTO @sub_label_order 
VALUES  ('Ratio', 3) ; 

WITH    Labels 
          AS ( 
              SELECT  DISTINCT 
                        src.Label + sublabel.SubLabel AS Label
                       ,ISNULL(label_order.Sort, 0) AS Sort 
                       ,ISNULL(sublabel.Sort, 0) AS SubSort 
              FROM      @src AS src 
              CROSS JOIN @sub_label_order AS sublabel
              LEFT JOIN @label_order AS label_order 
                        ON src.label = label_order.label 
             ) 
    SELECT  @pivot_cols = COALESCE(@pivot_cols + ',', '') + QUOTENAME(Label, '[') 
    FROM    Labels 
    ORDER BY Sort 
           ,SubSort
           ,Label ; 

DECLARE @template AS varchar(max) ; 

SET @template = ' 
DECLARE @src AS TABLE 
    ( 
     ID int NOT NULL 
    ,Label varchar(14) NOT NULL 
    ,Numerator int NOT NULL 
    ,Denominator int NOT NULL 
    ,Ratio decimal(5, 4) NOT NULL 
    ) ; 

INSERT  INTO @src 
VALUES  (1, ''LabelNameOne'', 41, 10, 4.1) ; 
INSERT  INTO @src 
VALUES  (1, ''LabelNameTwo'', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (1, ''LabelNameThree'', 21, 10, 2.1) ; 
INSERT  INTO @src 
VALUES  (1, ''LabelNameFour'', 15, 10, 1.5) ; 
INSERT  INTO @src 
VALUES  (2, ''LabelNameOne'', 19, 19, 1) ; 
INSERT  INTO @src 
VALUES  (2, ''LabelNameTwo'', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (2, ''LabelNameThree'', 15, 16, 0.9375) ; 
INSERT  INTO @src 
VALUES  (2, ''LabelNameFive'', 19, 19, 1) ; 
INSERT  INTO @src 
VALUES  (2, ''LabelNameSix'', 17, 17, 1) ; 
INSERT  INTO @src 
VALUES  (3, ''LabelNameOne'', 12, 12, 1) ; 
INSERT  INTO @src 
VALUES  (3, ''LabelNameTwo'', 0, 0, 0) ; 
INSERT  INTO @src 
VALUES  (3, ''LabelNameThree'', 11, 12, 0.9167) ; 
INSERT  INTO @src 
VALUES  (3, ''LabelNameFour'', 12, 12, 1) ; 
INSERT  INTO @src 
VALUES  (3, ''LabelNameSix'', 0, 1, 0) ; 

WITH    src_conformed 
          AS ( 
              SELECT    ID 
                       ,Label 
                       ,CAST (Numerator AS decimal(10, 4)) AS Numerator 
                       ,CAST (Denominator AS decimal(10, 4)) AS Denominator 
                       ,CAST (Ratio AS decimal(10, 4)) AS Ratio 
              FROM      @src 
             ), 
        UNPIVOTED 
          AS ( 
              SELECT    * 
              FROM      src_conformed UNPIVOT ( Val FOR Col IN (Numerator, Denominator, Ratio) ) AS unpvt 
             )
             ,COMBINED AS (SELECT  ID, Label + Col AS NewLabel, Val
    FROM    UNPIVOTED)
    SELECT *
    FROM    COMBINED PIVOT ( SUM(Val) FOR NewLabel IN ({@pivot_cols}) ) AS pvt 
     ORDER BY ID ;' ; 

SET @template = REPLACE(@template, '{@pivot_cols}', @pivot_cols) ; 

EXEC (@template) ;



  1. Database
  2.   
  3. Mysql
  4.   
  5. Oracle
  6.   
  7. Sqlserver
  8.   
  9. PostgreSQL
  10.   
  11. Access
  12.   
  13. SQLite
  14.   
  15. MariaDB
  1. Операторът ALTER TABLE е в конфликт

  2. SQL заявка за съвпадение на ключови думи?

  3. Каква е разликата между сканиране на таблица и сканиране на клъстерен индекс?

  4. Как да намерите таблици, които съдържат конкретна колона в SQL Server

  5. Трябва да изберете данни от една таблица след минус с една стойност