Има няколко начина, но мисля, че следният е най-популярен:
select allk.k, t1.c1, t2.v2, t3.v3, t4.v4
from (select k from t1 union
select k from t2 union
select k from t3 union
select k from t4
) allk left outer join
t1
on allk.k = t1.k left outer join
t2
on allk.k = t2.k left outer join
t3
on allk.k = t3.k left outer join
t4
on allk.k = t4.k;
Ако имате отделна таблица на всички k
стойности, можете да използвате това вместо allk
подзаявка.
По-лесен начин да напишете своето full outer join
заявката е да се използва coalesce()
:
SELECT COALESCE(t1.K, t2.K, t3.K, t4.K) [K], V1, V2, V3, V4
FROM @T1 t1 FULL JOIN
@T2 t2
ON t2.K = t1.K FULL JOIN
@T3 t3
ON t3.K = coalesce(t1.K, t2.K) FULL JOIN
@T4 t4
ON t4.K = coalesce(t1.K, t2.K, t3.k);
И третият метод е union all
/group by
метод:
select k, max(v1) as v1, max(v2) as v2, max(v3) as v3, max(v4) as v4
from (select k, v1, NULL as v2, NULL as v3, NULL as v4
from t1 union all
select k, NULL as v1, v2, NULL as v3, NULL as v4
from t2 union all
select k, NULL as v1, NULL as v2, v3, NULL as v4
from t3 union all
select k, NULL as v1, NULL as v2, NULL as v3, v4
from t4
) t
group by k;