Импортиране на SQL XML:Очакваше се XQuery [value()]:).

Зададохте много подобни въпроси. Взех информацията и от двамата и създадох този работещ пример. Имайте предвид xmlns-namespace, което трябва да бъде декларирано като „DEFAULT“:

Опростих вашия XML, но идеята трябва да е наред...

DECLARE @allUsers XML=
'<?xml version="1.0"?>
<?mso-application progid="Excel.Sheet"?>
<Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
 xmlns:o="urn:schemas-microsoft-com:office:office"
 xmlns:x="urn:schemas-microsoft-com:office:excel"
 xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
 xmlns:html="http://www.w3.org/TR/REC-html40">
 <Worksheet>
 <Table>
   <Row ss:AutoFitHeight="0" ss:Height="30">
    <Cell ss:StyleID="s22"/>
    <Cell ss:StyleID="s24"><Data ss:Type="String">Jane Doe</Data></Cell>
    <Cell ss:StyleID="s24"><Data ss:Type="String">JaneDoe</Data></Cell>
    <Cell ss:StyleID="s24"><Data ss:Type="String">XYZ</Data></Cell>
    <Cell ss:StyleID="s24"><Data ss:Type="String">(555) 555-5555</Data></Cell>
    <Cell ss:StyleID="s22"/>
   </Row>
   </Table>
 </Worksheet>   
</Workbook>';

;WITH XMLNAMESPACES ('urn:schemas-microsoft-com:office:spreadsheet' as ss
                     ,DEFAULT 'urn:schemas-microsoft-com:office:spreadsheet')
SELECT T.X.value('Cell[1]/Data[1]','varchar(max)') AS DontKnow1
      ,T.X.value('Cell[2]/Data[1]','varchar(max)') AS Name
      ,T.X.value('Cell[3]/Data[1]','varchar(max)') AS UserName
      ,T.X.value('Cell[4]/Data[1]','varchar(max)') AS DontKnow2
      ,T.X.value('Cell[5]/Data[1]','varchar(max)') AS Telephone
      ,T.X.value('Cell[6]/Data[1]','varchar(max)') AS DontKnow3
FROM @allUsers.nodes('/Workbook/Worksheet/Table/Row') as T(X)