Как да извлечете данни от xml колона в sql 2008

declare @T table
(
  XMLCol xml
)

insert into @T values
('<Menu>
    <Id>1</Id>
      <Url>http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-1.jpg</Url>
  </Menu>
  <Menu>
    <Id>2</Id>
    <Url>http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-2.jpg</Url>
  </Menu>
  <Menu>
    <Id>3</Id>
    <Url>http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-3.jpg</Url>
  </Menu>
  <Menu>
    <Id>4</Id>
    <Url>http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-4.jpg</Url>
  </Menu>
  <Menu>
    <Id>5</Id>
    <Url>http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-5.jpg</Url>
  </Menu>')

select X.N.value('Id[1]', 'int') as Id,
       X.N.value('Url[1]', 'varchar(max)') as Url
from @T as T
  cross apply T.XMLCol.nodes('/Menu') as X(N)

Резултат:

Id          Url
----------- ---------------------------------------------------------------------
1           http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-1.jpg
2           http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-2.jpg
3           http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-3.jpg
4           http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-4.jpg
5           http://www.zmtcdn.com/menus/1211/menu-photo-for-barbeque-nation-5.jpg