Редактиране:
Ако приемем, че вашите резултати са като тези:
Пишете
number company db1 Count
1 SuperCorp 5
2 SuperCorp 10
Докладване
number company db2 Count
2 SuperCorp 10
3 SuperCorp 20
Ако искате да покажете таблица като тази
number company db1 Count db2 Count
1 SuperCorp 5 0
2 SuperCorp 10 10
3 SuperCorp 0 20
Трябва да обедините резултатите от двете заявки, преди да ги отпечатате на екрана. Това е възможно благодарение на вашата колона 'number', която може да се използва като ключ на вашия PHP масив.
Трябва също така да промените вашите SQL заявки, за да включват фалшива колона, представяща другия брой на базата данни:
$sql1 = "SELECT num.number AS Number, com.name As company, count(*) As \"db1 count\", 0 As \"db2 count\"
FROM db1.db.job_processing AS jp
LEFT JOIN db1.db.number AS num ON num.id=jp.number_id
LEFT JOIN db1.db.company AS com on com.id=num.company_id
WHERE jp.show=1 AND jp.processing_complete=1
AND jp.call_start_time BETWEEN '2016-12-17' AND '2017-01-03'
GROUP BY Number
ORDER BY Number
LIMIT 20";
$sql2 = "SELECT num.number AS Number, com.name AS company, COUNT(*) AS \"db2 Count\", 0 As \"db1 count\"
FROM db2.db.job_processing AS jp
LEFT JOIN db2.db.number AS num ON num.id=jp.number_id
LEFT JOIN db2.db.company AS com on com.id=num.company_id
WHERE jp.show=1 AND jp.processing_complete=1
AND jp.call_start_time BETWEEN '2016-12-17' AND '2017-01-03'
GROUP BY Number
LIMIT 20";
И след това комбинирайте 2 резултата преди, за да ги покажете, като това :
$results = array();
while($row = $result1->fetch_assoc()) {
//Adding all the 1st query results
$results[$row['number']] = $row;
}
while($row = $result2->fetch_assoc()) {
if(! isset($results[$row['number']]) {
//Mean's this row is not present in the 1st database, so add it
$results[$row['number']] = $row;
}else {
//Just merging the db2 Count from the 2nd database since other fields are the same
$results[$row['number']]['db2 Count'] = $row['db2 Count'];
}
}
if ($results) {
echo"<TABLE><caption>Total Call Count Overview</caption><TR>
<TH>Number</TH>
<TH>Company</TH>
<TH>db1 Count</TH>
<TH>db2 Count</TH></TR>";
foreach($results as $row) {
echo"<TR><TD>". $row["number"]. "</TD>";
echo"<TD>". $row["company"]. "</TD>";
echo"<TD>". $row["db1 Count"]. "</TD>";
echo"<TD>". $row["db2 Count"]. "</TD></TR>";
}
echo"</TABLE>";
} else {
echo"0 Results";
}