Топ 10 на MYSql и общо други

За протокола, съгласен съм с коментара на @DamienBlack, но ако трябваше да се направи в една заявка UNION ALL може да свърши работа:

(
  SELECT VENDOR_fullname as name, SUM(POTENTIAL_RECOVERY) as recovery
  FROM COMPLETE
  GROUP BY VENDOR_fullname
  ORDER BY SUM(POTENTIAL_RECOVERY) DESC
  LIMIT 10
)
UNION ALL
(
  SELECT 'All others' as name, SUM(subtotal) as recovery
  FROM 
  (
    SELECT SUM(POTENTIAL_RECOVERY)
    FROM COMPLETE
    GROUP BY VENDOR_fullname
    ORDER BY SUM(POTENTIAL_RECOVERY) DESC
    LIMIT 10, 18446744073709551615
  ) as subtotal;
)