Изглежда, че се опитвате да направите това:
select d.RepName,
count(d.RepName) DoctorReportsCount,
count(h.RepName) HospitalsReportsCount,
d.DateAdded
from doctorreports d
inner join hospitals h
on d.RepName = h.RepName
group by d.RepName, d.DateAdded
редактиране:
select *
from
(
select d.RepName,
count(d.RepName) DoctorReportsCount
, d.dateadded
from doctorreports d
group by d.RepName, d.dateadded
) d
left join
(
select h.RepName,
count(h.RepName) HospitalsReportsCount
, h.dateadded hDateadded
from hospitals h
group by h.RepName, h.dateadded
)h
on d.RepName = h.RepName
вижте SQL Fiddle с демонстрация
редактиране #2, ако искате да върнете данни за дни, които липсват, тогава бих посъветвал да създадете таблица, която да съдържа календарни дати, след което можете да върнете данни за дните, които липсват. Следното трябва да върне това, което търсите. Имайте предвид, че създадох календарна таблица за тази заявка:
select COALESCE(d.drep, '') repname,
COALESCE(d.DCount, 0) DoctorReportsCount,
COALESCE(h.HCount, 0) HospitalsReportsCount,
c.dt Dateadded
from calendar c
left join
(
select repname drep,
count(repname) DCount,
dateadded ddate
from doctorreports
group by repname, dateadded
) d
on c.dt = d.ddate
left join
(
select repname hrep,
count(repname) HCount,
dateadded hdate
from hospitals
group by repname, dateadded
) h
on c.dt = h.hdate
and d.drep = h.hrep
вижте SQL Fiddle с демонстрация
Ако не ви пука за другите дати, тогава ето как бихте го направили без date таблица:
select COALESCE(d.RepName, '') repname,
COALESCE(d.DoctorReportsCount, 0) DoctorReportsCount,
COALESCE(h.HospitalsReportsCount, 0) HospitalsReportsCount,
COALESCE(p.PharmacyReportsCount, 0) PharmacyReportsCount,
d.dateadded Dateadded
from
(
select d.RepName,
count(d.RepName) DoctorReportsCount
, d.dateadded
from doctorreports d
group by d.RepName, d.dateadded
) d
left join
(
select h.RepName,
count(h.RepName) HospitalsReportsCount
, h.dateadded hDateadded
from hospitals h
group by h.RepName, h.dateadded
)h
on d.RepName = h.RepName
and d.dateadded = h.hDateadded
left join
(
select p.RepName,
count(p.RepName) PharmacyReportsCount
, p.dateadded hDateadded
from PharmacyReports p
group by p.RepName, p.dateadded
)p
on d.RepName = p.RepName
and d.dateadded = p.hDateadded
