Използвайте корелирана подзаявка:
SELECT COUNT(DISTINCT f_bankid) AS tcount
FROM tbl_fileStatus t
WHERE ? = (SELECT f_filestatus FROM tbl_fileStatus WHERE f_bankid = t.f_bankid ORDER BY f_id DESC LIMIT 1)
Заменете ?
с f_bankid
търсите.
Вижте демото
.
В MySql 8.0+ можете да използвате FIRST_VALUE()
функция на прозореца:
SELECT COUNT(*) AS tcount
FROM (
SELECT DISTINCT f_bankid,
FIRST_VALUE(f_filestatus) OVER (PARTITION BY f_bankid ORDER BY f_id DESC) f_filestatus
FROM tbl_fileStatus
) t
WHERE f_filestatus = ?
Вижте демото
.
Ако искате резултати за всички f_filestatus
в 1 ред:
SELECT
SUM(f_filestatus = 1) AS tcount1,
SUM(f_filestatus = 2) AS tcount2,
SUM(f_filestatus = 3) AS tcount3
FROM (
SELECT t.f_bankid, t.f_filestatus
FROM tbl_fileStatus t
WHERE t.f_id = (SELECT f_id FROM tbl_fileStatus WHERE f_bankid = t.f_bankid ORDER BY f_id DESC LIMIT 1)
) t
Вижте демото
.
Резултати:
> tcount1 | tcount2 | tcount3
> ------: | ------: | ------:
> 0 | 1 | 2