Добре, може би някой SQL магьосник би могъл да ви даде по-добро SQL решение. Но дотогава...
Ето как бих го направил с колекции на Laravel (сортиране с php):
$search_terms = array('York', 'North Yorkshire');
$properties = Property::where(function ($q) use ($search_terms) {
foreach ($search_terms as $value) {
$q->orWhere('address1', 'like', "%{$value}%");
$q->orWhere('address2', 'like', "%{$value}%");
$q->orWhere('postcode', 'like', "%{$value}%");
$q->orWhere('city_town', 'like', "%{$value}%");
$q->orWhere('county', 'like', "%{$value}%");
}
})->paginate(25);
$props = ['address1', 'address2', 'postcode', 'city_town', 'county'];
$properties = $properties->sortByDesc(function($i, $k) use ($search_terms, $props) {
// The bigger the weight, the higher the record
$weight = 0;
// Iterate through search terms
foreach($search_terms as $searchTerm) {
// Iterate through properties (address1, address2...)
foreach($props as $prop) {
// Use strpos instead of %value% (cause php)
if(strpos($i->{$prop}, $searchTerm) !== false)
$weight += 1; // Increase weight if the search term is found
}
}
return $weight;
});
$properties = $properties->values()->all();