sql заявка за сравняване на резултатите от следните заявки

Има много недоизказани неща. Надявам се да получавате по-ясни изисквания в ежедневната си работа ... Както и да е, ето симулация на вашата ситуация. Базира се на предположението, че дните с данни (един на седмица) са същите през 2007 г. и през 2008 г.:

SQL> create table lnd_wkly_plan_rx_summary (pd_end_dt,nrx_cnt)
  2  as
  3  select date '2008-09-07', 100000 from dual union all
  4  select date '2008-09-07', 536619.92 from dual union all
  5  select date '2008-09-14', 698082.03 from dual union all
  6  select date '2008-09-21', 403604.59 from dual union all
  7  select date '2008-09-21', 200000 from dual union all
  8  select date '2008-09-21', 100000 from dual union all
  9  select date '2008-09-28', 702457.36 from dual union all
 10  select date '2007-09-07', 400000 from dual union all
 11  select date '2007-09-14', 450000 from dual union all
 12  select date '2007-09-21', 500000 from dual union all
 13  select date '2007-09-28', 550000 from dual union all
 14  select date '2007-09-28', 100000 from dual
 15  /

Tabel is aangemaakt.

И вашите оригинални заявки, леко модифицирани.

SQL> SELECT pd_end_dt
  2       , SUM(nrx_cnt) Total_Count
  3    FROM lnd_wkly_plan_rx_summary
  4   WHERE pd_end_dt >= date '2008-09-01'
  5     AND pd_end_dt <  date '2008-09-30'
  6   GROUP BY pd_end_dt
  7  /

PD_END_DT           TOTAL_COUNT
------------------- -----------
07-09-2008 00:00:00   636619,92
14-09-2008 00:00:00   698082,03
21-09-2008 00:00:00   703604,59
28-09-2008 00:00:00   702457,36

4 rijen zijn geselecteerd.

SQL> SELECT pd_end_dt
  2       , SUM(nrx_cnt) Total_Count
  3    FROM lnd_wkly_plan_rx_summary
  4   WHERE pd_end_dt >= date '2007-09-01'
  5     AND pd_end_dt <  date '2007-09-30'
  6   GROUP BY pd_end_dt
  7  /

PD_END_DT           TOTAL_COUNT
------------------- -----------
07-09-2007 00:00:00      400000
14-09-2007 00:00:00      450000
21-09-2007 00:00:00      500000
28-09-2007 00:00:00      650000

4 rijen zijn geselecteerd.

И заявката, с която можете да сравните данните от 2007 г. и 2008 г.:

SQL> select to_char(pd_end_dt,'dd-mm') day_and_month
  2       , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
  3       , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
  4       , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
  5         - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) difference
  6       , (  sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end)
  7          - sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end)
  8         ) / sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) * 100 percentage_difference
  9    from lnd_wkly_plan_rx_summary
 10   where (  (   pd_end_dt >= date '2007-09-01'
 11            and pd_end_dt <  date '2007-09-30'
 12            )
 13         or (   pd_end_dt >= date '2008-09-07'
 14            and pd_end_dt <  date '2008-09-30'
 15            )
 16         )
 17   group by to_char(pd_end_dt,'dd-mm')
 18  /

DAY_A    SUM2007    SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09     400000  636619,92  236619,92            37,1681615
14-09     450000  698082,03  248082,03            35,5376617
21-09     500000  703604,59  203604,59            28,9373595
28-09     650000  702457,36   52457,36            7,46769313

4 rijen zijn geselecteerd.

Въпреки че е доста подробен, мисля, че говори сам за себе си. Може да ви хареса следното пренаписване, тъй като не повтаря агрегатните функции толкова много, колкото в заявката по-горе:

SQL> select day_and_month
  2       , sum2007
  3       , sum2008
  4       , sum2008-sum2007 difference
  5       , 100*(sum2008-sum2007)/sum2008 percentage_difference
  6    from ( select to_char(pd_end_dt,'dd-mm') day_and_month
  7                , sum(case trunc(pd_end_dt,'yyyy') when date '2007-01-01' then nrx_cnt end) sum2007
  8                , sum(case trunc(pd_end_dt,'yyyy') when date '2008-01-01' then nrx_cnt end) sum2008
  9             from lnd_wkly_plan_rx_summary
 10            where (   pd_end_dt >= date '2007-09-01'
 11                  and pd_end_dt <  date '2007-09-30'
 12                  )
 13               or (   pd_end_dt >= date '2008-09-07'
 14                  and pd_end_dt <  date '2008-09-30'
 15                  )
 16            group by to_char(pd_end_dt,'dd-mm')
 17         )
 18  /

DAY_A    SUM2007    SUM2008 DIFFERENCE PERCENTAGE_DIFFERENCE
----- ---------- ---------- ---------- ---------------------
07-09     400000  636619,92  236619,92            37,1681615
14-09     450000  698082,03  248082,03            35,5376617
21-09     500000  703604,59  203604,59            28,9373595
28-09     650000  702457,36   52457,36            7,46769313

4 rijen zijn geselecteerd.

Надявам се това да помогне.

Поздрави, Роб.