jackson десериализира обект със списък на интерфейса на spring

Мисля, че трябва да добавите персонализиран десериализатор

public class UserAccountAuthenticationSerializer extends JsonDeserializer<UserAccountAuthentication> {

@Override
public UserAccountAuthentication deserialize(JsonParser jsonParser, DeserializationContext deserializationContext)
        throws IOException {

    UserAccountAuthentication userAccountAuthentication = new UserAccountAuthentication();

    ObjectCodec oc = jsonParser.getCodec();
    JsonNode node = oc.readTree(jsonParser);
    userAccountAuthentication.setAuthenticated(node.get("authenticated").booleanValue());

    Iterator<JsonNode> elements = node.get("authorities").elements();
    while (elements.hasNext()) {
        JsonNode next = elements.next();
        JsonNode authority = next.get("authority");
        userAccountAuthentication.getAuthorities().add(new SimpleGrantedAuthority(authority.asText()));
    }
    return userAccountAuthentication;
}

}

Това е моят json

{"authenticated":true,"authorities":[{"authority":"role1"},{"authority":"role2"}],"details":null,"principal":null,"credentials":null,"name":null}

След това в горната част на вашето POJO

@JsonDeserialize(using = UserAccountAuthenticationSerializer.class)
public class UserAccountAuthentication  implements Authentication {

Ето теста

@Test
public void test1() throws IOException {

UserAccountAuthentication userAccountAuthentication = new UserAccountAuthentication();
userAccountAuthentication.setAuthenticated(true);
userAccountAuthentication.getAuthorities().add(new SimpleGrantedAuthority("role1"));
userAccountAuthentication.getAuthorities().add(new SimpleGrantedAuthority("role2"));

String json1 = new ObjectMapper().writeValueAsString(userAccountAuthentication);
UserAccountAuthentication readValue = new ObjectMapper().readValue(json1, UserAccountAuthentication.class);
String json2 = new ObjectMapper().writeValueAsString(readValue);
assertEquals(json1, json2);

}