Отговорът е:
string json = "{ 'foo' : 'bar' }";
MongoDB.Bson.BsonDocument document
= MongoDB.Bson.Serialization.BsonSerializer.Deserialize<BsonDocument>(json);
Отговорът е:
string json = "{ 'foo' : 'bar' }";
MongoDB.Bson.BsonDocument document
= MongoDB.Bson.Serialization.BsonSerializer.Deserialize<BsonDocument>(json);