Има много връзки за него. Вижте това.
http ://forums.asp.net/t/1104451.aspx/1?Как+да+изтеглим+видео+файл+от+sql+сървър+база+данни http://www.saurabhdeveloper.com/techtips_details.php?tipsid=15 http://forums.asp.net/p/1533758/3719583.aspx http://forums.asp.net/t/1045855.aspx/2 /10 http://forums.asp.net/t/1511588.aspx/1 http://www.dotnetspider.com /forum/274821-Play-video-file-asp-net-page.aspx http://blogs.ugidotnet.org/kfra/archive /2006/10/04/50003.aspx http://www.dotnetspider.com/resources/16239 -code-for-video-upload.aspx
http://www.c-sharpcorner.com/Forums/Thread/88899/ http://www.asp.net/webmatrix/tutorials/10 -работа-с-видео
http://www.c-sharpcorner.com/Forums/Thread/88899/
Опитайте този код
byte[] buffer;
//this is the array of bytes which will hold the data (file)
SqlConnection connection;
protected void ButtonUpload_Click(object sender, EventArgs e)
{
//check the file
if (FileUpload1.HasFile && FileUpload1.PostedFile != null
&& FileUpload1.PostedFile.FileName != "")
{
HttpPostedFile file = FileUpload1.PostedFile;
//retrieve the HttpPostedFile object
buffer = new byte[file.ContentLength];
int bytesReaded = file.InputStream.Read(buffer, 0,
FileUpload1.PostedFile.ContentLength);
if (bytesReaded > 0)
{
try
{
string connectionString =
ConfigurationManager.ConnectionStrings[
"uploadConnectionString"].ConnectionString;
connection = new SqlConnection(connectionString);
SqlCommand cmd = new SqlCommand
("INSERT INTO Videos (Video, Video_Name, Video_Size)" +
" VALUES (@video, @videoName, @videoSize)", connection);
cmd.Parameters.Add("@video",
SqlDbType.VarBinary, buffer.Length).Value = buffer;
cmd.Parameters.Add("@videoName",
SqlDbType.NVarChar).Value = FileUpload1.FileName;
cmd.Parameters.Add("@videoSize",
SqlDbType.BigInt).Value = file.ContentLength;
using (connection)
{
connection.Open();
int i = cmd.ExecuteNonQuery();
Label1.Text = "uploaded, " + i.ToString() + " rows affected";
}
}
catch (Exception ex)
{
Label1.Text = ex.Message.ToString();
}
}
}
else
{
Label1.Text = "Choose a valid video file";
}
}