Не мога да кажа дали вече го правите или не, но ще ви трябват дефинирани обекти на Oracle.
CREATE OR REPLACE TYPE SCHEMA."YOUR_OBJECT" AS OBJECT
(
field_one varchar2(50),
field_two varchar2(100)
);
/
CREATE OR REPLACE TYPE SCHEMA."YOUR_OBJECT_ARRAY" AS TABLE OF YOUR_OBJECT;
/
След това можете да напишете манипулатори на типове, които да съпоставят Java обектите с обектите на Oracle.
import oracle.sql.ARRAY;
import oracle.sql.ArrayDescriptor;
import oracle.sql.STRUCT;
import oracle.sql.StructDescriptor;
....
public class YourTypeHandler implements TypeHandler
{
....
public void setParameter(PreparedStatement ps, int i, Object parameter, JdbcType jdbcType) throws SQLException
{
List<YourObject> objects = (List<YourObject>) parameter;
StructDescriptor structDescriptor = StructDescriptor.createDescriptor("YOUR_OBJECT", ps.getConnection());
STRUCT[] structs = new STRUCT[objects.size()];
for (int index = 0; index < objects.size(); index++)
{
YourObject pack = packs.get(index);
Object[] params = new Object[2];
params[0] = pack.getFieldOne();
params[1] = pack.getFieldTwo();
STRUCT struct = new STRUCT(structDescriptor, ps.getConnection(), params);
structs[index] = struct;
}
ArrayDescriptor desc = ArrayDescriptor.createDescriptor("YOUR_OBJECT_ARRAY", ps.getConnection());
ARRAY oracleArray = new ARRAY(desc, ps.getConnection(), structs);
ps.setArray(i, oracleArray);
}
}
След това извикайте процедурата,
call your_proc
(
#{yourObjects, javaType=Object, jdbcType=ARRAY, jdbcTypeName=YOUR_OBJECT_ARRAY, mode=IN, typeHandler=YourObjectArrayTypeHandler}
)